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x^2-1.6x-1.36=0
a = 1; b = -1.6; c = -1.36;
Δ = b2-4ac
Δ = -1.62-4·1·(-1.36)
Δ = 8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8}=\sqrt{4*2}=\sqrt{4}*\sqrt{2}=2\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.6)-2\sqrt{2}}{2*1}=\frac{1.6-2\sqrt{2}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.6)+2\sqrt{2}}{2*1}=\frac{1.6+2\sqrt{2}}{2} $
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